an+1＝an+2n次方

Sn=2an+(-1)n次方怎么求anSn=2an+(-1)n次方怎么求anSn=2an+(-1)n次方怎么求ann=1时,a1=S1=2a1+(-1)a1=1n≥2时,an=Sn-S(n-1)=2a

an=an-1+2的n次方+n,a1=1,an=?an=an-1+2的n次方+n,a1=1,an=?an=an-1+2的n次方+n,a1=1,an=?用线性叠加原理a(n)=a(n-1)+2^n的解为

an中,a1=2,a(n+1)=3an+3(n+1)次方-2n次方,求anan中,a1=2,a(n+1)=3an+3(n+1)次方-2n次方,求anan中,a1=2,a(n+1)=3an+3(n+1)

a1等于1,an等于2an减1加2n次方,求an通项a1等于1,an等于2an减1加2n次方,求an通项a1等于1,an等于2an减1加2n次方,求an通项a1=1an=2a(n-1)+2^n两边同除

已知a1=1,an+1=an+2的n次方,求an.已知a1=1,an+1=an+2的n次方,求an.已知a1=1,an+1=an+2的n次方,求an.an＋1＆＃47；（2的n＋1次方）＝an＆＃47

已知an+1=2的n次方an,a1=2,求an通项已知an+1=2的n次方an,a1=2,求an通项已知an+1=2的n次方an,a1=2,求an通项累乘即可a(n+1)/an=2^n则an=a1*(

已知数列{an中}a1=3.且an+1=an+2的n次方已知数列{an中}a1=3.且an+1=an+2的n次方已知数列{an中}a1=3.且an+1=an+2的n次方an+1-an=2^nan-an

数列{an}中,a1=1,an+1=2an+2的n+1次方,证bn=an/2的n次方等比并求an.数列{an}中,a1=1,an+1=2an+2的n+1次方,证bn=an/2的n次方等比并求an.数列

等比数列{an}满足:a1=1/2,且an-an-1=1/2的n次方,求an等比数列{an}满足:a1=1/2,且an-an-1=1/2的n次方,求an等比数列{an}满足:a1=1/2,且an-an

a1=a2=1,an+2=3an+1+18an+2n次方求ana1=a2=1,an+2=3an+1+18an+2n次方求ana1=a2=1,an+2=3an+1+18an+2n次方求an先求特解令an

累乘法急用数列{an}中,a1=12(n-1)次方乘an=an-1求an累乘法急用数列{an}中,a1=12(n-1)次方乘an=an-1求an累乘法急用数列{an}中,a1=12(n-1)次方乘an

已知数列{an}中,a1=1,an=2an-1+3的n次方,求an急已知数列{an}中,a1=1,an=2an-1+3的n次方,求an急已知数列{an}中,a1=1,an=2an-1+3的n次方,求a

在数列{an}中,a1=1,an+1=2an+3~n,求an.为次方）在数列{an}中,a1=1,an+1=2an+3~n,求an.为次方）在数列{an}中,a1=1,an+1=2an+3~n,求an

如题数列{an}中a1=2an+1=an+（2的n次方）求通项公式an如题数列{an}中a1=2an+1=an+（2的n次方）求通项公式an如题数列{an}中a1=2an+1=an+（2的n次方）求通

在数列an中,A1=2,An+1=An+2n次方,求An的表达式在数列an中,A1=2,An+1=An+2n次方,求An的表达式在数列an中,A1=2,An+1=An+2n次方,求An的表达式a1=2

数列an中,a1=1,2an+1-2an=3,则通项an=n是下标,2后跟的是an+1和an次方数列an中,a1=1,2an+1-2an=3,则通项an=n是下标,2后跟的是an+1和an次方数列an

已知数列｛an｝的前n项和Sn=-an-（1／2）的n－1次方再加2,令bn＝2的n次方乘an,求证bn等差,还要求an已知数列｛an｝的前n项和Sn=-an-（1／2）的n－1次方再加2,令bn＝2

an=(2n+1)[(-1/2)的n次方]求an前项和an=(2n+1)[(-1/2)的n次方]求an前项和an=(2n+1)[(-1/2)的n次方]求an前项和错位相减法我今天上传图片已超过10个因

a(n+1)=an-2*3(n次方)+1,a1=3,求ana(n+1)=an-2*3(n次方)+1,a1=3,求ana(n+1)=an-2*3(n次方)+1,a1=3,求ana(n+1)=an-2*3

在数列an中,an=-2(n-(-1)n次方),求S10和S99在数列an中,an=-2(n-(-1)n次方),求S10和S99在数列an中,an=-2(n-(-1)n次方),求S10和S99由于（-