lim(x→0) (e^x-cosx)/x

lim(x→0)(e^x-cosx)/x=1? lim(x→0) (e^x-cosx)/x 求极限 lim e^x+e^-x-2cosx/x(e2x-1) x→0 lim(x趋向0)(e-e^cosx)/ln(1+x2) lim e-e^cosx除以xsinx x趋向0 lim（e＾x）cosx= x→+∞ lim(e^x-cosx)/xsinx x趋向0 求Lim(x→0)(sinx/x)^(cosx/1-cosx) lim(x→0)(1/cosx)=? lim(x趋向0)(1-e^cosx-1) 求极限lim (e^x^2)/cosx-1 区域0 lim(x→0)〖(∫[cosx,0](e^t-t)dt/x^4 〗 lim(e^(x^2)-1)/(cosx-1) ,x→0的极限为什么是-2 lim x→0 (1-cosx√cos2x√cos3x)/(e^x+1)sinx dx lim(x→0) (e的(X²)次方－1)÷(cosx－1) 求lim(1-cosx)/x^2求lim(1-COSX)/X^2X→0 用洛必达法则计算极限：limx→0 (e^x-cosx)/(sinx)lim x→π (sin3x)/(tan5x);lim x→0 (e^x+e^[-x]-2)/(1-cosx) ;lim x→0 [x(e^x+1)-2(e^x-1)]/x^3 ;lim x→π/2 (Insinx)/(π-2x)^2 lim (2sinx+cosx)^(1/x) 求极限 x→0用e^ln(2sinx+cosx)^(1/x) =(2sinx+cosx)^(1/x) 求