lim(x->无穷)[ln(1+1/x)]/[arc cotx]用洛必达法则求

来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/23 22:14:43
lim(x->无穷)[ln(1+1/x)]/[arccotx]用洛必达法则求lim(x->无穷)[ln(1+1/x)]/[arccotx]用洛必达法则求lim(x->无穷)[ln(1+1/x)]/[a

lim(x->无穷)[ln(1+1/x)]/[arc cotx]用洛必达法则求
lim(x->无穷)[ln(1+1/x)]/[arc cotx]用洛必达法则求

lim(x->无穷)[ln(1+1/x)]/[arc cotx]用洛必达法则求
lim(x->无穷)[ln(1+1/x)]/[arc cotx]
分子分母同时求导得lim(x->无穷)[ln(1+1/x)]/[arc cotx]
=lim(x->无穷)[[-1/(x^2+x)]/[-1/(1+x^2)] =lim(x->无穷)(1+x^2)/(x^2+x)=1