设M=1/(1+√2)+1/(√2+√3)+1/(√3+√4)+…+1/(√2011+√2012),N=1-2+3-4+5-6+…+2011-2012,求N/(M+1)²的值

来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/22 17:13:36
设M=1/(1+√2)+1/(√2+√3)+1/(√3+√4)+…+1/(√2011+√2012),N=1-2+3-4+5-6+…+2011-2012,求N/(M+1)²的值设M=1/(1+

设M=1/(1+√2)+1/(√2+√3)+1/(√3+√4)+…+1/(√2011+√2012),N=1-2+3-4+5-6+…+2011-2012,求N/(M+1)²的值
设M=1/(1+√2)+1/(√2+√3)+1/(√3+√4)+…+1/(√2011+√2012),N=1-2+3-4+5-6+…+2011-2012,
求N/(M+1)²的值

设M=1/(1+√2)+1/(√2+√3)+1/(√3+√4)+…+1/(√2011+√2012),N=1-2+3-4+5-6+…+2011-2012,求N/(M+1)²的值
通分=-1十根号2012,N=-1x2011÷2=-1006
共等于-1006/2012=-0.5.这也是我们老师昨天讲过的,