复数x0=3+2i,复数z满足z*z0 =3z+z0,则复数z=
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复数x0=3+2i,复数z满足z*z0=3z+z0,则复数z=复数x0=3+2i,复数z满足z*z0=3z+z0,则复数z=复数x0=3+2i,复数z满足z*z0=3z+z0,则复数z=z=a+bi(
复数x0=3+2i,复数z满足z*z0 =3z+z0,则复数z=
复数x0=3+2i,复数z满足z*z0 =3z+z0,则复数z=
复数x0=3+2i,复数z满足z*z0 =3z+z0,则复数z=
z=a+bi
(a+bi)(3+2i)=3(a+bi)+3+2i
(3a-2b)+(2a+3b)i=(3a+3)+(3b+2)i
所以
3a-2b=3a+3
2a+3b=3b+2
b=-3/2,a=1
所以z=1-3i/2
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