△ABC中,∠c=π/3求sinA+sinB+sinC取值范围

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△ABC中,∠c=π/3求sinA+sinB+sinC取值范围△ABC中,∠c=π/3求sinA+sinB+sinC取值范围△ABC中,∠c=π/3求sinA+sinB+sinC取值范围假定∠a>=∠

△ABC中,∠c=π/3求sinA+sinB+sinC取值范围
△ABC中,∠c=π/3求sinA+sinB+sinC取值范围

△ABC中,∠c=π/3求sinA+sinB+sinC取值范围
假定∠a>=∠b,因为∠c=π/3,那么设∠a=π/3+X,∠b=π/3-X
Y=sinA+sinB+sinC=sin(π/3+X)+sin(π/3-X)+sin(π/3)
=2*sin(π/3)*cos(x)+sin(π/3)
因为0>=X>π/3,所以 根下3