求(3n-sin(n^2))/(2n+cos(n^2))的极限,当n趋于无限大时

求极限(sin(2/n)+cos(3/n))^(-n) 求极限（sin^2)n/n+1 求极限lim(1/n)*[(sin(pi/n)+sin(2pi/n)+.+sin(n*pi/n)] n->无穷 求极限：lim((2n∧2-3n+1)/n+1)×sin n趋于无穷 令n趋近于无穷大,且n存在,求sin(π/n)+sin(2π/n)+sin(3π/n)+...+sin(π)=?. 求(3n-sin(n^2))/(2n+cos(n^2))的极限,当n趋于无限大时 高数求极限n趋于无穷大时,lim (1/n - sin(1/n))/ (1/n^2),lim (1/n - sin(1/n))/ (1/n^3)这一式子呢求极限n趋于无穷大时,lim (1/n - sin(1/n))/ (1/n^2),lim (1/n - sin(1/n))/ (1/n^3)这一式子呢? 如果极限limsin(n)/n=0,则lim)n-3sin(n))/(sin(n)-2n)=______ 当n趋于无穷时,求[sin(π/n)/(n+1)+sin(2π/n)/(n+1/2)+.sinπ/(n+1/n)]的极限 证明sin(pi/n)*sin(2pi/n)*sin(3pi/n)*…sin((n-1)pi/n)=n/(2^(n-1)) 组合计算题组合计算题 nC(n-3,n)+P(4,n)=4C(3,n+1)求nC（n+6,3n)+C(3n,n+7) C(17-2n)+C(3n 13+n)=? [1sin(1/n)]/[n²+n+1]+[2sin(2/n)]/[n²+n+2]+……+[nsin(n/n)]/[n²+n+n]求n趋于无穷大时极限? 求Lim (2sin^n x+3cos^n x)∕(sin^n x+cos^n x) ,0≤x≤π/2n趋于无穷大 紧急：求 lim n*sin(π(n^2+2)^0.5）*(-1)^n,n趋向无穷大； n*1+n*2+n*3+n*4.求公式 求最小值 ((n+2)(n+4))/(n(n+3)) (n-3)(n-2)(n-4)等于120 求n 求Sn=C(n,1)+2C(n,2)+...+nC(n,n)C(n,1)+2C(n,2)+...+nC(n,n) n是下标