lim√n+2-√n+1/√n+1-√n,x趋近于无穷大

用夹逼定理求lim(n→∞)[√(n^2+n)-n]^(1/n) 用夹逼定理求lim(n→∞)√[(n^2+n)-n]^(1/n) lim x→n (√n+1-√n)*√(n+1/2)lim x n→∞ (√n+1-√n)*√(n+1/2) lim(n->无限)(√ n)sinn/(n+1) 求极限lim n趋向于无穷（1/n）*√(n+1)(n+2)⋯(n+n) lim√n+2-√n+1/√n+1-√n,x趋近于无穷大 lim(n→∞)(sin(n+√(n^2+n)))^2lim(n→∞)(1/n!(1!+2!+…+n!)) 求极限lim(√(n^2-1) -n)/(n-√(n^2+1))的值 lim n→∞ n/√(2n+1)(n+1)= 极限lim(n→∞)√(n^2-3n)/2n+1 等于多少 lim √(n^2-3n)/2n+1 n→0 lim n〔√(n^2+1)-n〕当n→∞时的极限 lim√1+1/n^2 n趋向于无穷大 lim√[(3n^2)+1]/(7n+1)=? 利用定积分计算lim(1/√n(n+1)+1/√n(n+2)+……1/√n(n+n)) lim [√(3n+1)-√(3n)] /[√(5n+1)-√(5n)] lim(√n+1-√n)*√n,n趋近于无穷大 lim√n(√n+1-√n)（n趋近于无穷大）的极限