设z=x/(x+y),求二阶偏导
来源:学生作业帮助网 编辑:六六作业网 时间:2025/01/24 10:47:02
设z=x/(x+y),求二阶偏导设z=x/(x+y),求二阶偏导设z=x/(x+y),求二阶偏导Zx=[(x+y)-x]/(x+y)^2=y/(x+y)^2Zy=-x/(x+y)^2Zxx=-2y/(
设z=x/(x+y),求二阶偏导
设z=x/(x+y),求二阶偏导
设z=x/(x+y),求二阶偏导
Zx=[(x+y)-x]/(x+y)^2=y/(x+y)^2
Zy=-x/(x+y)^2
Zxx=-2y/(x+y)^3
Zyy=2x/(x+y)^3
Zxy=(x-y)/(x+y)^3
dz/dx=2sin(x+y)*cos(x+y) dz/dy=2sin(x+y)*cos(x+y)
d(dz/dx)/dx=2cos(x+y)*cos(x+y)-2sin(x+y)*sin(x+y)
d(dz/dy)/dy=2cos(x+y)*cos(x+y)-2sin(x+y)*sin(x+y)
d(dz/dx)/dy=2cos(x+y)*cos(x+y)-2sin(x+y)*sin(x+y)
设z=x/(x+y),求二阶偏导
设z=ln(x^z×y^x),求dz
设z=f(x,y)
设z=x^y,求dz
设Z=e^(x/y) 求a2z/axay 求二阶偏导
设z=z(x,y)由方程φ(x/z,y/z) 确定,证明x*∂z/∂x+y*∂z/∂y=z
设z=(x+y)/(x-y),求dz
设方程z^y=y^x 确定函数z=z(x,y) ,求∂z/∂x
设z=f(x^2-y^2,e^(xy)),求偏导z/x,偏导z/y
设Z=X+Y,其中X,Y满足X+2Y>=0,X-Y
设x,y,z为正数,且xyz(x+y+z)=4,则(x+y)(y+z)的最小值
设|x|-|y|+|z|=|x+y+z|,且|x+y|=4,|y+z|=5,|y|=3,求(x-y-z)^2的值
设x+y+z=11求函数u=2x*x+3y*y+z*z的最小值
设z=f(x,y)由方程z+x+y=e^(z+x+y)所确定,求Dz
设x+y+z=0,求x立方+x平方z-xyz+y平方z+y立方
设x,y,z属于R+,求证:x^4+y^4+z^4=(x+y+z)xyz
设X+Y+Z=0求X^3+X^2Z-XYZ+Y^2Z+Y^3的值
设z=f(x^2,y,y/x)可导,求δz/δx,δz/δy