lim(x→л/2)cosx/(x-л/2)
来源：学生作业帮助网 编辑：六六作业网 时间：2024/12/23 12:01:58
lim(x→л/2)cosx/(x-л/2)lim(x→л/2)cosx/(x-л/2)lim(x→л/2)cosx/(x-л/2)cosx=sin(л/2-x)所以原极限=lim(x→л/2)sin
lim(x→л/2)cosx/(x-л/2)
lim(x→л/2)cosx/(x-л/2)
lim(x→л/2)cosx/(x-л/2)
cosx=sin(л/2-x)
所以
原极限
=lim(x→л/2) sin(л/2-x) /(x-л/2)
=lim(x→л/2) -sin(x-л/2) /(x-л/2)
那么x→л/2的时候,x-л/2趋于0,
所以由重要极限lim(x→0) sinx /x=1可以知道,
原极限
=lim(x→л/2) -sin(x-л/2) /(x-л/2)
= -1
或者用洛必达法则,对分子分母同时求导,
得到
原极限
=lim(x→л/2) sin(л/2-x)' /(x-л/2)'
=lim(x→л/2) -cos(л/2-x) / 1
= -cos0
= -1
lim(x→л/2)cosx/(x-л/2)
求lim(1-cosx)/x^2求lim(1-COSX)/X^2X→0
lim(x→0)(cosx-cos^2x)/x^2
lim(x-cosx)/x x→-∞
lim(x→0)(cosx)^(1/ln(1+x^2))
lim(x→0)(cosx)^[4/(x^2)]
lim x→0[ln(cosx)]/x^2
lim(x→0)(cosx)^4/x^2 怎么解
limx→0(cosx)^(1/x^2)求解lim(x→0)((cosx)^(1/x^2))
求Lim(x→0)(sinx/x)^(cosx/1-cosx)
lim(x→0)[(secx)^2-1] /(1-cosx)
lim x→0(1+2cosx)^secx
lim(x→0)(1/cosx)=?
求极限lim(x→3)cosx
lim(x_sin)/(3x+2cosx)
已知lim(x→0) f(x)/(1-cosx) =2 求lim(x→0) [1+f(x)]^½
求lim x→0 (tan2x-sinx)/x以及lim x→0 (cosx-cos3x)/x^2
求函数的极限lim((x→x/2)cosx)/(cos(x/2)-sin(x/2))