1+(dy/dx)^2=y^2怎么解求y

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1+(dy/dx)^2=y^2怎么解求y1+(dy/dx)^2=y^2怎么解求y1+(dy/dx)^2=y^2怎么解求y(dy/dx)=sqrt(y^2-1)whichimplies:dy/sqrt(

1+(dy/dx)^2=y^2怎么解求y
1+(dy/dx)^2=y^2怎么解
求y

1+(dy/dx)^2=y^2怎么解求y
(dy/dx)=sqrt(y^2-1) which implies:dy/sqrt(y^2-1)=dx integrate both sides:integrate (1/sqrt(y^2-1))dy = x which leads to:ln|y+sqrt(y^2-1)|=x Please pay attention to the +/- after each steps.I didnt consider this issue here.