cos(xy)-ln[(x+y)/y]=y当x=0时怎么求导,

求解微分方程xy'ln(x)sin(y)+cos(y)(1-x*cos(y))=0 cos(xy)-ln[(x+y)/y]=y当x=0时怎么求导, xy=y'ln(y'/x) x/y=ln(xy)的导数 sin(xy)+ln(y-x)=x,求y` sin(xy)+ln(y-x)=x,求y 若x,y满足log[4cos²(xy)+1/4cos²(xy)]=lny-y/2+ln(e²/2),则ycos4x的值为 求方程xy''=y'ln(y'/x)的通解 微分方程xy''=y'ln(y'/x)的解 e^y+ln(xy)-e^(-x)=0,求y' 证明log(xy)=log(x)+log(y)或者ln(xy)=ln(x)+ln(y)一个意思 讲教一下师傅隐函数求导sinxy-ln(x+y)=0sinxy-ln(x+y)=0两边对X求导解:cos(xy)(y+xy')-(1+y)/(x+y)=0其中cos(xy)(y+xy')怎么得来的?要详细步骤(初学请谅解!谢谢!)隐函数y怎么处理呀?回答的好有追加分! y/x=ln(xy) 求dy/dx(xy-y^2)/(xy+x^2) sinxy-ln(x+y)=0两边对X求导 cos(xy)(y+xy')-(1+y‘)/(x+y)=0 其中(1+y‘)/(x+y)怎么得来的? y=ln[ln(ln x)] 求导 求导y=ln cos(2x+1) y=ln cos(e^x)的导数 函数y = ln | cosπ x | 的值域是?