(log2^3+3)=log2^24?是怎么得来的?
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(log2^3+3)=log2^24?是怎么得来的?(log2^3+3)=log2^24?是怎么得来的?(log2^3+3)=log2^24?是怎么得来的?对数公式：loga^M＋loga^N=log
(log2^3+3)=log2^24?是怎么得来的?
(log2^3+3)=log2^24?是怎么得来的?
(log2^3+3)=log2^24?是怎么得来的?
对数公式：
loga^M＋loga^N=loga^(MN)
nloga^M=loga^(M的n次方)
则原式=[log2^3]＋log2^8=log2^(3×8)=log2^24
同上
log2 6-log2 3
log2^6-log2^3
log2(4)/log2(3)
log2(3)×log2(4)=log2(7)?log2(3)×log2(4)=log2(7)吗?log2(1/49)+log2(1/16)+log2(1/27)等于多少呢?帮个忙!
[log2 1]+[log2 2]+[log2 3]+[log2 4]+[log2 5]+...+[log2 1024]=?[x]表示不超过x的最大整数2为底 答案是8204
(log2 9)/(log2 8) = 2/3(log2 3)
求值：log2 (5/56)^(1/2)+log2 (14)-(1/2)log2 (35)=log2中2为底数=1/2[-2log2 (7)-3]+log2 (2)+log2 (7) 中的1/2[-2log2 (7)-3]是怎么得到的？
(log2^3+3)=log2^24?是怎么得来的?
log2 14-2log2 7/3+log2 7-log2 18是多少2是小2
log2^5+3=
2log2^3=
log2 (x + 3) + log2(x + 2) = 1log2 (x + 3) + log2(x + 2) = 1
log2 3/log2 5等于log2 3-log2 5么?
计算：log2(log2 32-log2 3/4+log2 6)
已知log2 m=-1/log2 3,则m=
求解log2(3x)=log2(2x+1)
log2 3×log3 7=log2 7这个算法对吗
(log2 6)×(log3 6)-(log2 3+log3 2)=