log(a)(M-N)怎样算

log(a)(M-N)怎样算 log(a)M+log(a)N=? 证明a(log(m)n)=n(log(m)a) log a (m^n)=(log a m)^n? 推导log(a)(M/N) log(m+n)应该怎样计算 求证 log(a) (M·N)=log(a) M+log(a) N log(下标a)(M*N)是什么意思?= log(下标a)M+log(下标a)N log(a)M＝m,log(a)N＝n,怎么得出 log(a)(M×N)＝m+n log(a^n)M= 1/n log(a)(M) log(a^n)M= n log(a)(M) 哪个对啊求神回复 log(a)(mn)=log(a)(m)+log(a)(n)为什么呀? 证明对数运算法则（1）log(a)(MN)=log(a)(M)+log(a)(N); 　　（2）log(a)(M/N)=log(a)(M)-log(a)(N);（1）log(a)(MN)=log(a)(M)+log(a)(N); 　　（2）log(a)(M/N)=log(a)(M)-log(a)(N); 　　（3）log(a)(M^n)=nlog(a)(M) （n∈R） log a b^n/log a a^m 什么运算法则得log a b^n/m 证明log(a^m)b^n=(n/m)log(a)b 为什么log(a^n)(M)=1/n×log(a)(M) log a^m(b^n)=(n/m)*log a(b) 求对数函数公式的推导log(a)(M^n)=nlog(a)(M) 和log(a)(N)=log(b)(N) / log(b)(a) 的推导 证明：log(a)(M^n)=nlog(a)(M)