dy/dx+x^3(y-x)^2=1求微分方程的通解

x^2+xy+y^3=1,求dy/dx 求方程 dy/dx+x(y-x) +x^3(y-x)^2=1的通解~ y=f[(x-1)/(x+1)],f'(x)=arctanx^2,求dy/dx,dy y=Insin(3x-1),求dx分之dy 设y=√(x^2-1)求dy/dx 求dy/dx-2y/x=1的通解 设y=sin2x/(1+x^2),求dy/dx, 设y=sin2x/(1+x^2),求dy/dx, 求dy/dx y=e^(2x+1) 设y=（x/1-x)^x,求dy/dx 求微分方程通解dy/dx=(x-2y+1)/(2x+3y+2) 求微分方程通解：dy/dx=(x-y+1)/(x+y^2+3) x^y-y^x=2,求dy/dx 求dy/dx=(x-y+5)/(x+y-2) 求下列微分方程的通解,对于有初始条件的,1、dy/dx+y=e^-x2、dy/dx-2y/x+1=(x+1)^33、x*dy/dx+y=3,y(1)=0可+分 (x^2)dy+（y^2)dx=dx-dy matlab中如何表示dy/dx=y/A式并求A?x=1:2:10 y=x.^3 dy/dx=y/A dy/dx+((2-3x^2)/x^3)y=1 求通解