(2)-(-10)^2n×100×(-10)^2n-1
来源:学生作业帮助网 编辑:六六作业网 时间:2025/01/11 19:18:24
(2)-(-10)^2n×100×(-10)^2n-1(2)-(-10)^2n×100×(-10)^2n-1(2)-(-10)^2n×100×(-10)^2n-1原式=-10^2n×10^2×10^(
(2)-(-10)^2n×100×(-10)^2n-1
(2)-(-10)^2n×100×(-10)^2n-1
(2)-(-10)^2n×100×(-10)^2n-1
原式=-10^2n×10^2×10^(2n-1)
=-10^(2n+2+2n-1)
=-10^(4n+1)
n+(n+1)+(n+2)+(n+3)+(n+4)=5n+10这道题怎么解
2^n/n*(n+1)
证明不等式:(1/n)^n+(2/n)^n+(3/n)^n+.+(n/n)^n
(n+2)!/(n+1)!
解方程(2n+1)(n+1)n-(2n-21)(n-10)(n-11)=2(2n-9)(n-4)(n-5)
当n为正整数时,定义函数N(n)表示n的最大奇因数.N(3)=3N(10)=5S(n)=N(1)+N(2)+N(3)+...+N(2^n)当n为正整数时,定义函数N(n)表示n的最大奇因数.如N(3)=3N(10)=5.记S(n)=N(1)+N(2)+N(3)+...+N(2^n)则S(4)=---- S(n)=------求
[n(n-1)+100]/2n求最小值
3^[n+2]-4*3^[n+1]+10*3^n
数列(n-10)(1/2)^n前n项和
(2)-(-10)^2n×100×(-10)^2n-1
-(-10)^2n*100*(-10)^2n-1
(n)(n+1)分之1+(n+1)(n+2)分之1……(n+99)(n+100)分之1 化简
n是自然数,0≤n≤101,则| n-1|+|n-2|+|n-3|+…+|n-100|的最小值,
1/N(N+I)+1/(N+1)(N+2)+1/(N+2)(N+3)+.+1/(N+9)(N+10)如何做?
[3n(n+1)+n(n+1)(2n+1)]/6+n(n+2)化简
[3n(n+1)+n(n+1)(2n+1)]/6+n(n+2)化简
化简n分之n-1+n分之n-2+n分之n-3+.+n分之1
化简n分之n-1+n分之n-2+n分之n-3+.+n分之1