已知复数z满足(1+2i)z=4+3i,求z
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已知复数z满足(1+2i)z=4+3i,求z已知复数z满足(1+2i)z=4+3i,求z已知复数z满足(1+2i)z=4+3i,求z由(1+2i)z=4+3i得z=(4+3i)/(1+2i)=(4+3
已知复数z满足(1+2i)z=4+3i,求z
已知复数z满足(1+2i)z=4+3i,求z
已知复数z满足(1+2i)z=4+3i,求z
由(1+2i)z=4+3i
得z=(4+3i)/(1+2i)
=(4+3i)(1-2i)/[(1+2i)(1-2i)]
=(4+3i-8i-6i²)/(1-4i²)
=(10-5i)/5
=2-i
答案:z=2-i
设z=b+ai,有:
b-2a=4
2b+a=3
解得a=-1,b=2
所以z=2-i
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